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mvpa2.clfs.transerror.linregress

mvpa2.clfs.transerror.linregress(x, y=None)

Calculate a regression line

This computes a least-squares regression for two sets of measurements.

Parameters :

x, y : array_like

two sets of measurements. Both arrays should have the same length. If only x is given (and y=None), then it must be a two-dimensional array where one dimension has length 2. The two sets of measurements are then found by splitting the array along the length-2 dimension.

Returns :

slope : float

slope of the regression line

intercept : float

intercept of the regression line

r-value : float

correlation coefficient

p-value : float

two-sided p-value for a hypothesis test whose null hypothesis is that the slope is zero.

stderr : float

Standard error of the estimate

Examples

>>> from scipy import stats
>>> import numpy as np
>>> x = np.random.random(10)
>>> y = np.random.random(10)
>>> slope, intercept, r_value, p_value, std_err = stats.linregress(x,y)

# To get coefficient of determination (r_squared)

>>> print "r-squared:", r_value**2
r-squared: 0.15286643777